Base | Representation |
---|---|
bin | 1100010010100010010… |
… | …0110000100110101101 |
3 | 202011222022002201002121 |
4 | 3010220210300212231 |
5 | 11424400313404123 |
6 | 240554344552541 |
7 | 21153046300204 |
oct | 3045044604655 |
9 | 664868081077 |
10 | 211134122413 |
11 | 815a5787165 |
12 | 34b04482751 |
13 | 16ba9c767a6 |
14 | a30cb0623b |
15 | 575aba875d |
hex | 31289309ad |
211134122413 has 4 divisors (see below), whose sum is σ = 211760633500. Its totient is φ = 210507611328.
The previous prime is 211134122383. The next prime is 211134122431. The reversal of 211134122413 is 314221431112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 111835398724 + 99298723689 = 334418^2 + 315117^2 .
It is a cyclic number.
It is not a de Polignac number, because 211134122413 - 213 = 211134114221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211134122443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 313255038 + ... + 313255711.
It is an arithmetic number, because the mean of its divisors is an integer number (52940158375).
Almost surely, 2211134122413 is an apocalyptic number.
It is an amenable number.
211134122413 is a deficient number, since it is larger than the sum of its proper divisors (626511087).
211134122413 is an equidigital number, since it uses as much as digits as its factorization.
211134122413 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 626511086.
The product of its digits is 1152, while the sum is 25.
Adding to 211134122413 its reverse (314221431112), we get a palindrome (525355553525).
The spelling of 211134122413 in words is "two hundred eleven billion, one hundred thirty-four million, one hundred twenty-two thousand, four hundred thirteen".
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