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21113433302011 = 235915558904423
BaseRepresentation
bin1001100110011110110101…
…01100010010001111111011
32202202102110110122201110121
410303033122230102033323
510231410302411131021
6112523213301554111
74306252362646141
oct463173254221773
982672413581417
1021113433302011
11680017a744716
12244bb12115937
13ba1cb016220b
1452dc77843591
1526931ed29741
hex1333dab123fb

21113433302011 has 8 divisors (see below), whose sum is σ = 22404822370560. Its totient is φ = 19853162042472.

The previous prime is 21113433302009. The next prime is 21113433302041. The reversal of 21113433302011 is 11020333431112.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21113433302011 - 21 = 21113433302009 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (21113433302041) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7779450855 + ... + 7779453568.

It is an arithmetic number, because the mean of its divisors is an integer number (2800602796320).

Almost surely, 221113433302011 is an apocalyptic number.

21113433302011 is a deficient number, since it is larger than the sum of its proper divisors (1291389068549).

21113433302011 is a wasteful number, since it uses less digits than its factorization.

21113433302011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15558904505.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 21113433302011 its reverse (11020333431112), we get a palindrome (32133766733123).

The spelling of 21113433302011 in words is "twenty-one trillion, one hundred thirteen billion, four hundred thirty-three million, three hundred two thousand, eleven".

Divisors: 1 23 59 1357 15558904423 357854801729 917975360957 21113433302011