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2111400303983 is a prime number
BaseRepresentation
bin11110101110011001010…
…000111101110101101111
321110211220010011122021122
4132232121100331311233
5234043121434211413
64253544112051155
7305354316315305
oct36563120756557
97424803148248
102111400303983
11744492478013
122a1253833abb
13124147bb81c9
1474299a24275
1539dc7eca108
hex1eb9943dd6f

2111400303983 has 2 divisors, whose sum is σ = 2111400303984. Its totient is φ = 2111400303982.

The previous prime is 2111400303967. The next prime is 2111400304001. The reversal of 2111400303983 is 3893030041112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2111400303983 - 24 = 2111400303967 is a prime.

It is a super-2 number, since 2×21114003039832 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111400323983) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055700151991 + 1055700151992.

It is an arithmetic number, because the mean of its divisors is an integer number (1055700151992).

Almost surely, 22111400303983 is an apocalyptic number.

2111400303983 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111400303983 is an equidigital number, since it uses as much as digits as its factorization.

2111400303983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 2111400303983 in words is "two trillion, one hundred eleven billion, four hundred million, three hundred three thousand, nine hundred eighty-three".