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21114121341 = 37038040447
BaseRepresentation
bin10011101010011111…
…111110110001111101
32000111110221111102010
4103222133332301331
5321220203340331
613411044521433
71345141033035
oct235237766175
960443844363
1021114121341
118a55409965
1241130b0279
131cb6461031
14104425c8c5
15838990e46
hex4ea7fec7d

21114121341 has 4 divisors (see below), whose sum is σ = 28152161792. Its totient is φ = 14076080892.

The previous prime is 21114121339. The next prime is 21114121349. The reversal of 21114121341 is 14312141112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 21114121341 - 21 = 21114121339 is a prime.

It is a super-2 number, since 2×211141213412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21114121349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3519020221 + ... + 3519020226.

It is an arithmetic number, because the mean of its divisors is an integer number (7038040448).

Almost surely, 221114121341 is an apocalyptic number.

It is an amenable number.

21114121341 is a deficient number, since it is larger than the sum of its proper divisors (7038040451).

21114121341 is an equidigital number, since it uses as much as digits as its factorization.

21114121341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7038040450.

The product of its digits is 192, while the sum is 21.

Adding to 21114121341 its reverse (14312141112), we get a palindrome (35426262453).

The spelling of 21114121341 in words is "twenty-one billion, one hundred fourteen million, one hundred twenty-one thousand, three hundred forty-one".

Divisors: 1 3 7038040447 21114121341