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2111420213653 is a prime number
BaseRepresentation
bin11110101110011010011…
…100111010100110010101
321110211221111122011012211
4132232122130322212111
5234043142033314103
64253550102513421
7305354650460062
oct36563234724625
97424844564184
102111420213653
117444a2736493
122a125a435871
1312414c06948a
147429c527c69
1539dc9b0e36d
hex1eb9a73a995

2111420213653 has 2 divisors, whose sum is σ = 2111420213654. Its totient is φ = 2111420213652.

The previous prime is 2111420213633. The next prime is 2111420213659. The reversal of 2111420213653 is 3563120241112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1769437360804 + 341982852849 = 1330202^2 + 584793^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111420213653 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2111420213659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055710106826 + 1055710106827.

It is an arithmetic number, because the mean of its divisors is an integer number (1055710106827).

Almost surely, 22111420213653 is an apocalyptic number.

It is an amenable number.

2111420213653 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111420213653 is an equidigital number, since it uses as much as digits as its factorization.

2111420213653 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 31.

Adding to 2111420213653 its reverse (3563120241112), we get a palindrome (5674540454765).

The spelling of 2111420213653 in words is "two trillion, one hundred eleven billion, four hundred twenty million, two hundred thirteen thousand, six hundred fifty-three".