211143115111 has 2 divisors, whose sum is σ = 211143115112. Its totient is φ = 211143115110.

The previous prime is 211143115103. The next prime is 211143115231. The reversal of 211143115111 is 111511341112.

It is a m-pointer prime, because the next prime (211143115231) can be obtained adding 211143115111 to its product of digits (120).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211143115111 - 2³ = 211143115103 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211143118111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105571557555 + 105571557556.

It is an arithmetic number, because the mean of its divisors is an integer number (105571557556).

Almost surely, 2^211143115111 is an apocalyptic number.

211143115111 is a deficient number, since it is larger than the sum of its proper divisors (1).

211143115111 is an equidigital number, since it uses as much as digits as its factorization.

211143115111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 120, while the sum is 22.

Adding to 211143115111 its reverse (111511341112), we get a palindrome (322654456223).

The spelling of 211143115111 in words is "two hundred eleven billion, one hundred forty-three million, one hundred fifteen thousand, one hundred eleven".