211143133141 has 4 divisors (see below), whose sum is σ = 217954201984. Its totient is φ = 204332064300.

The previous prime is 211143133127. The next prime is 211143133211. The reversal of 211143133141 is 141331341112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 211143133141 - 2⁵ = 211143133109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (211143133111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3405534375 + ... + 3405534436.

It is an arithmetic number, because the mean of its divisors is an integer number (54488550496).

Almost surely, 2^211143133141 is an apocalyptic number.

It is an amenable number.

211143133141 is a deficient number, since it is larger than the sum of its proper divisors (6811068843).

211143133141 is an equidigital number, since it uses as much as digits as its factorization.

211143133141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6811068842.

The product of its digits is 864, while the sum is 25.

Adding to 211143133141 its reverse (141331341112), we get a palindrome (352474474253).

The spelling of 211143133141 in words is "two hundred eleven billion, one hundred forty-three million, one hundred thirty-three thousand, one hundred forty-one".