Base | Representation |
---|---|
bin | 1001100110100010100010… |
… | …10100011111101101100011 |
3 | 2202202121121011200000111011 |
4 | 10303101101110133231203 |
5 | 10231423341412220103 |
6 | 112524143000001351 |
7 | 4306352610552223 |
oct | 463212124375543 |
9 | 82677534600434 |
10 | 21115423554403 |
11 | 6801001133802 |
12 | 2450388760257 |
13 | ba22395a5859 |
14 | 52ddc5cc2083 |
15 | 2693d9913d6d |
hex | 13345151fb63 |
21115423554403 has 2 divisors, whose sum is σ = 21115423554404. Its totient is φ = 21115423554402.
The previous prime is 21115423554299. The next prime is 21115423554461. The reversal of 21115423554403 is 30445532451112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21115423554403 - 213 = 21115423546211 is a prime.
It is a super-2 number, since 2×211154235544032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21115423554503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10557711777201 + 10557711777202.
It is an arithmetic number, because the mean of its divisors is an integer number (10557711777202).
Almost surely, 221115423554403 is an apocalyptic number.
21115423554403 is a deficient number, since it is larger than the sum of its proper divisors (1).
21115423554403 is an equidigital number, since it uses as much as digits as its factorization.
21115423554403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288000, while the sum is 40.
The spelling of 21115423554403 in words is "twenty-one trillion, one hundred fifteen billion, four hundred twenty-three million, five hundred fifty-four thousand, four hundred three".
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