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2111550161473 is a prime number
BaseRepresentation
bin11110101110100010001…
…100101000001001000001
321110212021120011012010001
4132232202030220021001
5234043423320131343
64254011024040001
7305361116142514
oct36564214501101
97425246135101
102111550161473
1174455a022185
122a1295a63001
1312416cc6728c
14742b18b2d7b
1539dd622c44d
hex1eba2328241

2111550161473 has 2 divisors, whose sum is σ = 2111550161474. Its totient is φ = 2111550161472.

The previous prime is 2111550161431. The next prime is 2111550161519. The reversal of 2111550161473 is 3741610551112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1431200683584 + 680349477889 = 1196328^2 + 824833^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2111550161473 is a prime.

It is not a weakly prime, because it can be changed into another prime (2111550161173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1055775080736 + 1055775080737.

It is an arithmetic number, because the mean of its divisors is an integer number (1055775080737).

Almost surely, 22111550161473 is an apocalyptic number.

It is an amenable number.

2111550161473 is a deficient number, since it is larger than the sum of its proper divisors (1).

2111550161473 is an equidigital number, since it uses as much as digits as its factorization.

2111550161473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25200, while the sum is 37.

The spelling of 2111550161473 in words is "two trillion, one hundred eleven billion, five hundred fifty million, one hundred sixty-one thousand, four hundred seventy-three".