21120011101121 has 4 divisors (see below), whose sum is σ = 21120020753712. Its totient is φ = 21120001448532.

The previous prime is 21120011101051. The next prime is 21120011101171. The reversal of 21120011101121 is 12110111002112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 21120011101121 - 2¹⁴ = 21120011084737 is a prime.

It is a super-3 number, since 3×21120011101121³ (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21120011101096 and 21120011101105.

It is not an unprimeable number, because it can be changed into a prime (21120011101171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 201926 + ... + 6502368.

It is an arithmetic number, because the mean of its divisors is an integer number (5280005188428).

Almost surely, 2^{21120011101121} is an apocalyptic number.

It is an amenable number.

21120011101121 is a deficient number, since it is larger than the sum of its proper divisors (9652591).

21120011101121 is an equidigital number, since it uses as much as digits as its factorization.

21120011101121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9652590.

The product of its (nonzero) digits is 8, while the sum is 14.

Adding to 21120011101121 its reverse (12110111002112), we get a palindrome (33230122103233).

Subtracting from 21120011101121 its reverse (12110111002112), we obtain a palindrome (9009900099009).

The spelling of 21120011101121 in words is "twenty-one trillion, one hundred twenty billion, eleven million, one hundred one thousand, one hundred twenty-one".