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2112001321231 is a prime number
BaseRepresentation
bin11110101110111101000…
…101101010100100001111
321110220110000002110221201
4132232331011222210033
5234100334314234411
64254123502010331
7305405235012214
oct36567505524417
97426400073851
102112001321231
1174477076018a
122a13a0b769a7
1312421257bb09
1474315793b0b
1539e10b493c1
hex1ebbd16a90f

2112001321231 has 2 divisors, whose sum is σ = 2112001321232. Its totient is φ = 2112001321230.

The previous prime is 2112001321207. The next prime is 2112001321237. The reversal of 2112001321231 is 1321231002112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2112001321231 - 231 = 2109853837583 is a prime.

It is a super-2 number, since 2×21120013212312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2112001321199 and 2112001321208.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112001321237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056000660615 + 1056000660616.

It is an arithmetic number, because the mean of its divisors is an integer number (1056000660616).

Almost surely, 22112001321231 is an apocalyptic number.

2112001321231 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112001321231 is an equidigital number, since it uses as much as digits as its factorization.

2112001321231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2112001321231 its reverse (1321231002112), we get a palindrome (3433232323343).

The spelling of 2112001321231 in words is "two trillion, one hundred twelve billion, one million, three hundred twenty-one thousand, two hundred thirty-one".