Search a number
-
+
21120111212147 is a prime number
BaseRepresentation
bin1001100110101011010001…
…01110011111011001110011
32202210001200212022201000122
410303111220232133121303
510232012441432242042
6112530240052440455
74306610021153663
oct463255056373163
982701625281018
1021120111212147
116802a971a7412
12245127661912b
13ba280580492c
1453030c6ba1a3
152695b121e7d2
hex133568b9f673

21120111212147 has 2 divisors, whose sum is σ = 21120111212148. Its totient is φ = 21120111212146.

The previous prime is 21120111212059. The next prime is 21120111212177. The reversal of 21120111212147 is 74121211102112.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21120111212147 - 210 = 21120111211123 is a prime.

It is a super-2 number, since 2×211201112121472 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21120111212177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560055606073 + 10560055606074.

It is an arithmetic number, because the mean of its divisors is an integer number (10560055606074).

Almost surely, 221120111212147 is an apocalyptic number.

21120111212147 is a deficient number, since it is larger than the sum of its proper divisors (1).

21120111212147 is an equidigital number, since it uses as much as digits as its factorization.

21120111212147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 448, while the sum is 26.

Adding to 21120111212147 its reverse (74121211102112), we get a palindrome (95241322314259).

The spelling of 21120111212147 in words is "twenty-one trillion, one hundred twenty billion, one hundred eleven million, two hundred twelve thousand, one hundred forty-seven".