Base | Representation |
---|---|
bin | 1001100110101011010010… |
… | …11000000001100100111111 |
3 | 2202210001201121210212101121 |
4 | 10303111221120001210333 |
5 | 10232013002224200111 |
6 | 112530241122051411 |
7 | 4306610212542043 |
oct | 463255130014477 |
9 | 82701647725347 |
10 | 21120122100031 |
11 | 6802aa2363669 |
12 | 245127a1a9b67 |
13 | ba2807b47676 |
14 | 53030dd12023 |
15 | 2695b2170871 |
hex | 13356960193f |
21120122100031 has 2 divisors, whose sum is σ = 21120122100032. Its totient is φ = 21120122100030.
The previous prime is 21120122099971. The next prime is 21120122100041. The reversal of 21120122100031 is 13000122102112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21120122100031 - 235 = 21085762361663 is a prime.
It is a super-2 number, since 2×211201221000312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21120122099978 and 21120122100014.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21120122100041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560061050015 + 10560061050016.
It is an arithmetic number, because the mean of its divisors is an integer number (10560061050016).
Almost surely, 221120122100031 is an apocalyptic number.
21120122100031 is a deficient number, since it is larger than the sum of its proper divisors (1).
21120122100031 is an equidigital number, since it uses as much as digits as its factorization.
21120122100031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 21120122100031 its reverse (13000122102112), we get a palindrome (34120244202143).
The spelling of 21120122100031 in words is "twenty-one trillion, one hundred twenty billion, one hundred twenty-two million, one hundred thousand, thirty-one".
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