Base | Representation |
---|---|
bin | 1100010010110010010… |
… | …1000000110001010101 |
3 | 202012010222111112222112 |
4 | 3010230211000301111 |
5 | 11430020013004433 |
6 | 241005144440405 |
7 | 21154523260004 |
oct | 3045445006125 |
9 | 665128445875 |
10 | 211201297493 |
11 | 8162a69885a |
12 | 34b22a79105 |
13 | 16bbab66564 |
14 | a3179d0c3b |
15 | 5761a27348 |
hex | 312c940c55 |
211201297493 has 2 divisors, whose sum is σ = 211201297494. Its totient is φ = 211201297492.
The previous prime is 211201297481. The next prime is 211201297537. The reversal of 211201297493 is 394792102112.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 158275074244 + 52926223249 = 397838^2 + 230057^2 .
It is a cyclic number.
It is not a de Polignac number, because 211201297493 - 212 = 211201293397 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 211201297493.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211201297423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105600648746 + 105600648747.
It is an arithmetic number, because the mean of its divisors is an integer number (105600648747).
Almost surely, 2211201297493 is an apocalyptic number.
It is an amenable number.
211201297493 is a deficient number, since it is larger than the sum of its proper divisors (1).
211201297493 is an equidigital number, since it uses as much as digits as its factorization.
211201297493 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 41.
The spelling of 211201297493 in words is "two hundred eleven billion, two hundred one million, two hundred ninety-seven thousand, four hundred ninety-three".
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