Base | Representation |
---|---|
bin | 110000000001011000100010… |
… | …101001011110111000000111 |
3 | 1000200210122110221121102122221 |
4 | 300001120202221132320013 |
5 | 210140310232044110343 |
6 | 2025104312245233211 |
7 | 62325535114653103 |
oct | 6001304251367007 |
9 | 1020718427542587 |
10 | 211201303113223 |
11 | 61327a73667735 |
12 | 1b830289102807 |
13 | 90b027498a0c7 |
14 | 3a222aa36c903 |
15 | 1963c6d2c55ed |
hex | c01622a5ee07 |
211201303113223 has 2 divisors, whose sum is σ = 211201303113224. Its totient is φ = 211201303113222.
The previous prime is 211201303113187. The next prime is 211201303113247. The reversal of 211201303113223 is 322311303102112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 211201303113223 - 233 = 211192713178631 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211201303113253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105600651556611 + 105600651556612.
It is an arithmetic number, because the mean of its divisors is an integer number (105600651556612).
Almost surely, 2211201303113223 is an apocalyptic number.
211201303113223 is a deficient number, since it is larger than the sum of its proper divisors (1).
211201303113223 is an equidigital number, since it uses as much as digits as its factorization.
211201303113223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 211201303113223 its reverse (322311303102112), we get a palindrome (533512606215335).
The spelling of 211201303113223 in words is "two hundred eleven trillion, two hundred one billion, three hundred three million, one hundred thirteen thousand, two hundred twenty-three".
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