Base | Representation |
---|---|
bin | 110000000001011010010100… |
… | …011001000010001101000111 |
3 | 1000200210211101221101122121221 |
4 | 300001122110121002031013 |
5 | 210140323134104412403 |
6 | 2025105225454421211 |
7 | 62325633316113262 |
oct | 6001322431021507 |
9 | 1020724357348557 |
10 | 211203211404103 |
11 | 61328862865936 |
12 | 1b830720201807 |
13 | 90b04ba1345c9 |
14 | 3a2240b993cd9 |
15 | 1963d30abedbd |
hex | c01694642347 |
211203211404103 has 4 divisors (see below), whose sum is σ = 211226754296968. Its totient is φ = 211179668511240.
The previous prime is 211203211404089. The next prime is 211203211404109. The reversal of 211203211404103 is 301404112302112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 211203211404103 - 217 = 211203211273031 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (211203211404109) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11771432976 + ... + 11771450917.
It is an arithmetic number, because the mean of its divisors is an integer number (52806688574242).
Almost surely, 2211203211404103 is an apocalyptic number.
211203211404103 is a deficient number, since it is larger than the sum of its proper divisors (23542892865).
211203211404103 is an equidigital number, since it uses as much as digits as its factorization.
211203211404103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23542892864.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 211203211404103 its reverse (301404112302112), we get a palindrome (512607323706215).
The spelling of 211203211404103 in words is "two hundred eleven trillion, two hundred three billion, two hundred eleven million, four hundred four thousand, one hundred three".
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