Base | Representation |
---|---|
bin | 11110101110111111011… |
… | …101000101000010111001 |
3 | 21110220112202210001102021 |
4 | 132232333131011002321 |
5 | 234100424444412213 |
6 | 4254131440434441 |
7 | 305406226256011 |
oct | 36567735050271 |
9 | 7426482701367 |
10 | 2112041013433 |
11 | 74479110055a |
12 | 2a13b2318a21 |
13 | 12421a868520 |
14 | 7431ab66c41 |
15 | 39e14389d8d |
hex | 1ebbf7450b9 |
2112041013433 has 16 divisors (see below), whose sum is σ = 2323240206336. Its totient is φ = 1907816063040.
The previous prime is 2112041013413. The next prime is 2112041013437. The reversal of 2112041013433 is 3343101402112.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2112041013433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2112041013398 and 2112041013407.
It is not an unprimeable number, because it can be changed into a prime (2112041013437) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3972535 + ... + 4472707.
It is an arithmetic number, because the mean of its divisors is an integer number (145202512896).
Almost surely, 22112041013433 is an apocalyptic number.
It is an amenable number.
2112041013433 is a deficient number, since it is larger than the sum of its proper divisors (211199192903).
2112041013433 is a wasteful number, since it uses less digits than its factorization.
2112041013433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 507144.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 2112041013433 its reverse (3343101402112), we get a palindrome (5455142415545).
The spelling of 2112041013433 in words is "two trillion, one hundred twelve billion, forty-one million, thirteen thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •