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2112041013437 is a prime number
BaseRepresentation
bin11110101110111111011…
…101000101000010111101
321110220112202210001102102
4132232333131011002331
5234100424444412222
64254131440434445
7305406226256015
oct36567735050275
97426482701372
102112041013437
11744791100563
122a13b2318a25
1312421a868524
147431ab66c45
1539e14389d92
hex1ebbf7450bd

2112041013437 has 2 divisors, whose sum is σ = 2112041013438. Its totient is φ = 2112041013436.

The previous prime is 2112041013413. The next prime is 2112041013443. The reversal of 2112041013437 is 7343101402112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1769501211076 + 342539802361 = 1330226^2 + 585269^2 .

It is a cyclic number.

It is not a de Polignac number, because 2112041013437 - 216 = 2112040947901 is a prime.

It is a super-3 number, since 3×21120410134373 (a number of 38 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112041213437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056020506718 + 1056020506719.

It is an arithmetic number, because the mean of its divisors is an integer number (1056020506719).

Almost surely, 22112041013437 is an apocalyptic number.

It is an amenable number.

2112041013437 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112041013437 is an equidigital number, since it uses as much as digits as its factorization.

2112041013437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4032, while the sum is 29.

Adding to 2112041013437 its reverse (7343101402112), we get a palindrome (9455142415549).

The spelling of 2112041013437 in words is "two trillion, one hundred twelve billion, forty-one million, thirteen thousand, four hundred thirty-seven".