Base | Representation |
---|---|
bin | 1100010010110011000… |
… | …0100101001110011111 |
3 | 202012011012012122100101 |
4 | 3010230300211032133 |
5 | 11430021302033044 |
6 | 241005333441531 |
7 | 21154561121206 |
oct | 3045460451637 |
9 | 665135178311 |
10 | 211204330399 |
11 | 8163137a497 |
12 | 34b23aa02a7 |
13 | 16bbb688b8a |
14 | a31818023d |
15 | 5761e25cd4 |
hex | 312cc2539f |
211204330399 has 2 divisors, whose sum is σ = 211204330400. Its totient is φ = 211204330398.
The previous prime is 211204330387. The next prime is 211204330417. The reversal of 211204330399 is 993033402112.
211204330399 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211204330399 - 211 = 211204328351 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211204330369) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105602165199 + 105602165200.
It is an arithmetic number, because the mean of its divisors is an integer number (105602165200).
Almost surely, 2211204330399 is an apocalyptic number.
211204330399 is a deficient number, since it is larger than the sum of its proper divisors (1).
211204330399 is an equidigital number, since it uses as much as digits as its factorization.
211204330399 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34992, while the sum is 37.
The spelling of 211204330399 in words is "two hundred eleven billion, two hundred four million, three hundred thirty thousand, three hundred ninety-nine".
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