2112050211433 has 4 divisors (see below), whose sum is σ = 2112418362580. Its totient is φ = 2111682060288.

The previous prime is 2112050211419. The next prime is 2112050211539. The reversal of 2112050211433 is 3341120502112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 988857214569 + 1123192996864 = 994413^2 + 1059808^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2112050211433 is a prime.

It is a super-2 number, since 2×2112050211433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2112050211398 and 2112050211407.

It is not an unprimeable number, because it can be changed into a prime (2112050211413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 184066968 + ... + 184078441.

It is an arithmetic number, because the mean of its divisors is an integer number (528104590645).

Almost surely, 2^{2112050211433} is an apocalyptic number.

It is an amenable number.

2112050211433 is a deficient number, since it is larger than the sum of its proper divisors (368151147).

2112050211433 is an equidigital number, since it uses as much as digits as its factorization.

2112050211433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 368151146.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 2112050211433 its reverse (3341120502112), we get a palindrome (5453170713545).

The spelling of 2112050211433 in words is "two trillion, one hundred twelve billion, fifty million, two hundred eleven thousand, four hundred thirty-three".