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211205916043753 is a prime number
BaseRepresentation
bin110000000001011100110101…
…100110011010100111101001
31000200211002101102122120201211
4300001130311212122213221
5210140344204001400003
62025110354112313121
762326060330142131
oct6001346546324751
91020732342576654
10211205916043753
1161329a20530714
121b831155b427a1
1390b082b583ab7
143a225c6c73ac1
151963e3d26e96d
hexc0173599a9e9

211205916043753 has 2 divisors, whose sum is σ = 211205916043754. Its totient is φ = 211205916043752.

The previous prime is 211205916043711. The next prime is 211205916043757. The reversal of 211205916043753 is 357340619502112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 184408034814864 + 26797881228889 = 13579692^2 + 5176667^2 .

It is a cyclic number.

It is not a de Polignac number, because 211205916043753 - 241 = 209006892788201 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 211205916043697 and 211205916043706.

It is not a weakly prime, because it can be changed into another prime (211205916043757) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105602958021876 + 105602958021877.

It is an arithmetic number, because the mean of its divisors is an integer number (105602958021877).

Almost surely, 2211205916043753 is an apocalyptic number.

It is an amenable number.

211205916043753 is a deficient number, since it is larger than the sum of its proper divisors (1).

211205916043753 is an equidigital number, since it uses as much as digits as its factorization.

211205916043753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1360800, while the sum is 49.

The spelling of 211205916043753 in words is "two hundred eleven trillion, two hundred five billion, nine hundred sixteen million, forty-three thousand, seven hundred fifty-three".