Base | Representation |
---|---|
bin | 11110101111000010111… |
… | …110000011011101011101 |
3 | 21110220200212202100011011 |
4 | 132233002332003131131 |
5 | 234101040044124331 |
6 | 4254141344455221 |
7 | 305410543456306 |
oct | 36570276033535 |
9 | 7426625670134 |
10 | 2112099989341 |
11 | 744811421a81 |
12 | 2a140a01a511 |
13 | 124229b47304 |
14 | 743249197ad |
15 | 39e196393b1 |
hex | 1ebc2f8375d |
2112099989341 has 2 divisors, whose sum is σ = 2112099989342. Its totient is φ = 2112099989340.
The previous prime is 2112099989333. The next prime is 2112099989347. The reversal of 2112099989341 is 1439899902112.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1415693049241 + 696406940100 = 1189829^2 + 834510^2 .
It is a cyclic number.
It is not a de Polignac number, because 2112099989341 - 23 = 2112099989333 is a prime.
It is a super-2 number, since 2×21120999893412 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112099989347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056049994670 + 1056049994671.
It is an arithmetic number, because the mean of its divisors is an integer number (1056049994671).
Almost surely, 22112099989341 is an apocalyptic number.
It is an amenable number.
2112099989341 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112099989341 is an equidigital number, since it uses as much as digits as its factorization.
2112099989341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2519424, while the sum is 58.
The spelling of 2112099989341 in words is "two trillion, one hundred twelve billion, ninety-nine million, nine hundred eighty-nine thousand, three hundred forty-one".
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