Base | Representation |
---|---|
bin | 11110101111000010111… |
… | …110100001001101101011 |
3 | 21110220200212222112022212 |
4 | 132233002332201031223 |
5 | 234101040112024321 |
6 | 4254141351235335 |
7 | 305410544504516 |
oct | 36570276411553 |
9 | 7426625875285 |
10 | 2112100111211 |
11 | 7448114a55a2 |
12 | 2a140a078b4b |
13 | 124229b8a91c |
14 | 7432494bd7d |
15 | 39e1966055b |
hex | 1ebc2fa136b |
2112100111211 has 4 divisors (see below), whose sum is σ = 2112123813000. Its totient is φ = 2112076409424.
The previous prime is 2112100111183. The next prime is 2112100111223. The reversal of 2112100111211 is 1121110012112.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2112100111211 - 238 = 1837222204267 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2112100111241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11716721 + ... + 11895618.
It is an arithmetic number, because the mean of its divisors is an integer number (528030953250).
Almost surely, 22112100111211 is an apocalyptic number.
2112100111211 is a deficient number, since it is larger than the sum of its proper divisors (23701789).
2112100111211 is an equidigital number, since it uses as much as digits as its factorization.
2112100111211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23701788.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 2112100111211 its reverse (1121110012112), we get a palindrome (3233210123323).
Subtracting from 2112100111211 its reverse (1121110012112), we obtain a palindrome (990990099099).
The spelling of 2112100111211 in words is "two trillion, one hundred twelve billion, one hundred million, one hundred eleven thousand, two hundred eleven".
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