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2112101120083 is a prime number
BaseRepresentation
bin11110101111000011000…
…010010111100001010011
321110220200221212210020111
4132233003002113201103
5234101040341320313
64254141425022151
7305410556206033
oct36570302274123
97426627783214
102112101120083
11744812024579
122a140a484957
1312422a151ba6
1474324b318c3
1539e197ae43d
hex1ebc3097853

2112101120083 has 2 divisors, whose sum is σ = 2112101120084. Its totient is φ = 2112101120082.

The previous prime is 2112101120053. The next prime is 2112101120113. The reversal of 2112101120083 is 3800211012112.

It is a balanced prime because it is at equal distance from previous prime (2112101120053) and next prime (2112101120113).

It is a cyclic number.

It is not a de Polignac number, because 2112101120083 - 213 = 2112101111891 is a prime.

It is a super-2 number, since 2×21121011200832 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2112101120023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056050560041 + 1056050560042.

It is an arithmetic number, because the mean of its divisors is an integer number (1056050560042).

Almost surely, 22112101120083 is an apocalyptic number.

2112101120083 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112101120083 is an equidigital number, since it uses as much as digits as its factorization.

2112101120083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 192, while the sum is 22.

Adding to 2112101120083 its reverse (3800211012112), we get a palindrome (5912312132195).

The spelling of 2112101120083 in words is "two trillion, one hundred twelve billion, one hundred one million, one hundred twenty thousand, eighty-three".