Base | Representation |
---|---|
bin | 110000000001100000110101… |
… | …100110011010111000011001 |
3 | 1000200211111110202101120201100 |
4 | 300001200311212122320121 |
5 | 210140432003004341441 |
6 | 2025112344220342013 |
7 | 62326301631600606 |
oct | 6001406546327031 |
9 | 1020744422346640 |
10 | 211210211012121 |
11 | 61330824971a52 |
12 | 1b831b543a4909 |
13 | 90b1064330cb9 |
14 | 3a228b344b6ad |
15 | 19640e035ccb6 |
hex | c0183599ae19 |
211210211012121 has 24 divisors (see below), whose sum is σ = 305766617181480. Its totient is φ = 140490832896000.
The previous prime is 211210211012117. The next prime is 211210211012159. The reversal of 211210211012121 is 121210112012112.
It is a happy number.
211210211012121 is a `hidden beast` number, since 211 + 210 + 2 + 110 + 12 + 121 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 51306219562896 + 159903991449225 = 7162836^2 + 12645315^2 .
It is not a de Polignac number, because 211210211012121 - 22 = 211210211012117 is a prime.
It is a super-3 number, since 3×2112102110121213 (a number of 44 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 211210211012094 and 211210211012103.
It is not an unprimeable number, because it can be changed into a prime (211210211012321) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2035656 + ... + 20653433.
It is an arithmetic number, because the mean of its divisors is an integer number (12740275715895).
Almost surely, 2211210211012121 is an apocalyptic number.
It is an amenable number.
211210211012121 is a deficient number, since it is larger than the sum of its proper divisors (94556406169359).
211210211012121 is a wasteful number, since it uses less digits than its factorization.
211210211012121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22691417 (or 22691414 counting only the distinct ones).
The product of its (nonzero) digits is 32, while the sum is 18.
Adding to 211210211012121 its reverse (121210112012112), we get a palindrome (332420323024233).
Subtracting from 211210211012121 its reverse (121210112012112), we obtain a palindrome (90000099000009).
The spelling of 211210211012121 in words is "two hundred eleven trillion, two hundred ten billion, two hundred eleven million, twelve thousand, one hundred twenty-one".
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