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211210342081 is a prime number
BaseRepresentation
bin1100010010110100011…
…1100000111011000001
3202012011121112001211021
43010231013200323001
511430024321421311
6241010110345441
721154663200034
oct3045507407301
9665147461737
10211210342081
1181634806122
1234b25abb281
1316bbc9b229b
14a318ca701b
155762712171
hex312d1e0ec1

211210342081 has 2 divisors, whose sum is σ = 211210342082. Its totient is φ = 211210342080.

The previous prime is 211210342069. The next prime is 211210342127. The reversal of 211210342081 is 180243012112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 113782083856 + 97428258225 = 337316^2 + 312135^2 .

It is a cyclic number.

It is not a de Polignac number, because 211210342081 - 29 = 211210341569 is a prime.

It is a super-2 number, since 2×2112103420812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211210342001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605171040 + 105605171041.

It is an arithmetic number, because the mean of its divisors is an integer number (105605171041).

Almost surely, 2211210342081 is an apocalyptic number.

It is an amenable number.

211210342081 is a deficient number, since it is larger than the sum of its proper divisors (1).

211210342081 is an equidigital number, since it uses as much as digits as its factorization.

211210342081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 211210342081 its reverse (180243012112), we get a palindrome (391453354193).

The spelling of 211210342081 in words is "two hundred eleven billion, two hundred ten million, three hundred forty-two thousand, eighty-one".