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211211099993 is a prime number
BaseRepresentation
bin1100010010110100101…
…0011001111101011001
3202012011122221120111002
43010231022121331121
511430030020144433
6241010134514345
721155002504505
oct3045512317531
9665148846432
10211211099993
11816351835a3
1234b262059b5
1316bbcbb925a
14a319023305
1557628119e8
hex312d299f59

211211099993 has 2 divisors, whose sum is σ = 211211099994. Its totient is φ = 211211099992.

The previous prime is 211211099987. The next prime is 211211099999. The reversal of 211211099993 is 399990112112.

It is a balanced prime because it is at equal distance from previous prime (211211099987) and next prime (211211099999).

It can be written as a sum of positive squares in only one way, i.e., 209826292624 + 1384807369 = 458068^2 + 37213^2 .

It is a cyclic number.

It is not a de Polignac number, because 211211099993 - 214 = 211211083609 is a prime.

It is a super-2 number, since 2×2112110999932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211211099999) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605549996 + 105605549997.

It is an arithmetic number, because the mean of its divisors is an integer number (105605549997).

Almost surely, 2211211099993 is an apocalyptic number.

It is an amenable number.

211211099993 is a deficient number, since it is larger than the sum of its proper divisors (1).

211211099993 is an equidigital number, since it uses as much as digits as its factorization.

211211099993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78732, while the sum is 47.

The spelling of 211211099993 in words is "two hundred eleven billion, two hundred eleven million, ninety-nine thousand, nine hundred ninety-three".