211211110497823 has 2 divisors, whose sum is σ = 211211110497824. Its totient is φ = 211211110497822.

The previous prime is 211211110497817. The next prime is 211211110497857. The reversal of 211211110497823 is 328794011112112.

211211110497823 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 211211110497823 - 2²¹ = 211211108400671 is a prime.

It is a super-2 number, since 2×211211110497823² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 211211110497823.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (211211110497223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605555248911 + 105605555248912.

It is an arithmetic number, because the mean of its divisors is an integer number (105605555248912).

Almost surely, 2^{211211110497823} is an apocalyptic number.

211211110497823 is a deficient number, since it is larger than the sum of its proper divisors (1).

211211110497823 is an equidigital number, since it uses as much as digits as its factorization.

211211110497823 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 43.

The spelling of 211211110497823 in words is "two hundred eleven trillion, two hundred eleven billion, one hundred ten million, four hundred ninety-seven thousand, eight hundred twenty-three".