211211111113 has 2 divisors, whose sum is σ = 211211111114. Its totient is φ = 211211111112.

The previous prime is 211211111099. The next prime is 211211111129. The reversal of 211211111113 is 311111112112.

It is an a-pointer prime, because the next prime (211211111129) can be obtained adding 211211111113 to its sum of digits (16).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 181499004729 + 29712106384 = 426027^2 + 172372^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211211111113 is a prime.

It is a super-2 number, since 2×211211111113² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211211111143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105605555556 + 105605555557.

It is an arithmetic number, because the mean of its divisors is an integer number (105605555557).

Almost surely, 2^211211111113 is an apocalyptic number.

It is an amenable number.

211211111113 is a deficient number, since it is larger than the sum of its proper divisors (1).

211211111113 is an equidigital number, since it uses as much as digits as its factorization.

211211111113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12, while the sum is 16.

Adding to 211211111113 its reverse (311111112112), we get a palindrome (522322223225).

Subtracting 211211111113 from its reverse (311111112112), we obtain a palindrome (99900000999).

The spelling of 211211111113 in words is "two hundred eleven billion, two hundred eleven million, one hundred eleven thousand, one hundred thirteen".