Base | Representation |
---|---|
bin | 110000000001100001101011… |
… | …110001111110101011100010 |
3 | 1000200211120211002211120010121 |
4 | 300001201223301332223202 |
5 | 210140440333210341002 |
6 | 2025113014331350454 |
7 | 62326333310142205 |
oct | 6001415361765342 |
9 | 1020746732746117 |
10 | 211211120012002 |
11 | 61331150a91020 |
12 | 1b8321688b242a |
13 | 90b117a758c56 |
14 | 3a2295c06b93c |
15 | 1964145066237 |
hex | c0186bc7eae2 |
211211120012002 has 32 divisors (see below), whose sum is σ = 348527632803840. Its totient is φ = 95198556240720.
The previous prime is 211211120011951. The next prime is 211211120012089. The reversal of 211211120012002 is 200210021112112.
It is a super-2 number, since 2×2112111200120022 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 39444618 + ... + 44478085.
It is an arithmetic number, because the mean of its divisors is an integer number (10891488525120).
Almost surely, 2211211120012002 is an apocalyptic number.
211211120012002 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
211211120012002 is a deficient number, since it is larger than the sum of its proper divisors (137316512791838).
211211120012002 is a wasteful number, since it uses less digits than its factorization.
211211120012002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 83923678.
The product of its (nonzero) digits is 32, while the sum is 16.
Adding to 211211120012002 its reverse (200210021112112), we get a palindrome (411421141124114).
The spelling of 211211120012002 in words is "two hundred eleven trillion, two hundred eleven billion, one hundred twenty million, twelve thousand, two".
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