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211211120202002 = 2105605560101001
BaseRepresentation
bin110000000001100001101011…
…110010101101000100010010
31000200211120211010012012202122
4300001201223302231010102
5210140440333232431002
62025113014335414242
762326333311563144
oct6001415362550422
91020746733165678
10211211120202002
1161331151100848
121b832168984382
1390b117a7c458b
143a2295c0bac94
1519641450a26a2
hexc0186bcad112

211211120202002 has 4 divisors (see below), whose sum is σ = 316816680303006. Its totient is φ = 105605560101000.

The previous prime is 211211120201989. The next prime is 211211120202023. The reversal of 211211120202002 is 200202021112112.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 199159523287321 + 12051596914681 = 14112389^2 + 3471541^2 .

It is a super-2 number, since 2×2112111202020022 (a number of 29 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52802780050499 + ... + 52802780050502.

Almost surely, 2211211120202002 is an apocalyptic number.

211211120202002 is a deficient number, since it is larger than the sum of its proper divisors (105605560101004).

211211120202002 is a wasteful number, since it uses less digits than its factorization.

211211120202002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 105605560101003.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 211211120202002 its reverse (200202021112112), we get a palindrome (411413141314114).

The spelling of 211211120202002 in words is "two hundred eleven trillion, two hundred eleven billion, one hundred twenty million, two hundred two thousand, two".

Divisors: 1 2 105605560101001 211211120202002