Base | Representation |
---|---|
bin | 1001100110101101001011… |
… | …01000101110101100110111 |
3 | 2202210011100002012121020202 |
4 | 10303112211220232230313 |
5 | 10232022040034041434 |
6 | 112530525315351115 |
7 | 4306644240156125 |
oct | 463264550565467 |
9 | 82704302177222 |
10 | 21121133112119 |
11 | 6803471018a47 |
12 | 24515008b249b |
13 | ba293943bc81 |
14 | 5303a82c8915 |
15 | 269620cc9a7e |
hex | 1335a5a2eb37 |
21121133112119 has 2 divisors, whose sum is σ = 21121133112120. Its totient is φ = 21121133112118.
The previous prime is 21121133112089. The next prime is 21121133112137. The reversal of 21121133112119 is 91121133112112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21121133112119 - 28 = 21121133111863 is a prime.
It is a super-2 number, since 2×211211331121192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21121133112091 and 21121133112100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21121133112179) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560566556059 + 10560566556060.
It is an arithmetic number, because the mean of its divisors is an integer number (10560566556060).
Almost surely, 221121133112119 is an apocalyptic number.
21121133112119 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121133112119 is an equidigital number, since it uses as much as digits as its factorization.
21121133112119 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 648, while the sum is 29.
The spelling of 21121133112119 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred thirty-three million, one hundred twelve thousand, one hundred nineteen".
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