Base | Representation |
---|---|
bin | 1001100110101101001100… |
… | …00011000011111111111111 |
3 | 2202210011100120012022100211 |
4 | 10303112212003003333333 |
5 | 10232022043320440403 |
6 | 112530530123333251 |
7 | 4306644352636342 |
oct | 463264603037777 |
9 | 82704316168324 |
10 | 21121140015103 |
11 | 6803474a03297 |
12 | 2451503081227 |
13 | ba293a9b7c8b |
14 | 5303a91a4459 |
15 | 2696216e006d |
hex | 1335a60c3fff |
21121140015103 has 2 divisors, whose sum is σ = 21121140015104. Its totient is φ = 21121140015102.
The previous prime is 21121140015077. The next prime is 21121140015193. The reversal of 21121140015103 is 30151004112112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21121140015103 is a prime.
It is a super-2 number, since 2×211211400151032 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21121140015193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560570007551 + 10560570007552.
It is an arithmetic number, because the mean of its divisors is an integer number (10560570007552).
Almost surely, 221121140015103 is an apocalyptic number.
21121140015103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121140015103 is an equidigital number, since it uses as much as digits as its factorization.
21121140015103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 22.
Adding to 21121140015103 its reverse (30151004112112), we get a palindrome (51272144127215).
The spelling of 21121140015103 in words is "twenty-one trillion, one hundred twenty-one billion, one hundred forty million, fifteen thousand, one hundred three".
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