Search a number
-
+
211212000000241 is a prime number
BaseRepresentation
bin110000000001100010100000…
…001110110111100011110001
31000200211200002102200121001121
4300001202200032313203301
5210140444134000001431
62025113241524502241
762326364154002452
oct6001424016674361
91020750072617047
10211212000000241
1161331562795229
121b83237354a981
1390b128ab66a56
143a22a02c99129
15196419743d611
hexc018a03b78f1

211212000000241 has 2 divisors, whose sum is σ = 211212000000242. Its totient is φ = 211212000000240.

The previous prime is 211212000000167. The next prime is 211212000000251. The reversal of 211212000000241 is 142000000212112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 188076429097216 + 23135570903025 = 13714096^2 + 4809945^2 .

It is a cyclic number.

It is not a de Polignac number, because 211212000000241 - 221 = 211211997903089 is a prime.

It is a super-2 number, since 2×2112120000002412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211212000000251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606000000120 + 105606000000121.

It is an arithmetic number, because the mean of its divisors is an integer number (105606000000121).

Almost surely, 2211212000000241 is an apocalyptic number.

It is an amenable number.

211212000000241 is a deficient number, since it is larger than the sum of its proper divisors (1).

211212000000241 is an equidigital number, since it uses as much as digits as its factorization.

211212000000241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64, while the sum is 16.

Adding to 211212000000241 its reverse (142000000212112), we get a palindrome (353212000212353).

The spelling of 211212000000241 in words is "two hundred eleven trillion, two hundred twelve billion, two hundred forty-one", and thus it is an aban number.