Base | Representation |
---|---|
bin | 110000000001100010100000… |
… | …001110110111100010100111 |
3 | 1000200211200002102200120221212 |
4 | 300001202200032313202213 |
5 | 210140444134000001132 |
6 | 2025113241524502035 |
7 | 62326364154002315 |
oct | 6001424016674247 |
9 | 1020750072616855 |
10 | 211212000000167 |
11 | 61331562795171 |
12 | 1b83237354a91b |
13 | 90b128ab669ca |
14 | 3a22a02c990b5 |
15 | 196419743d5b2 |
hex | c018a03b78a7 |
211212000000167 has 2 divisors, whose sum is σ = 211212000000168. Its totient is φ = 211212000000166.
The previous prime is 211212000000143. The next prime is 211212000000241. The reversal of 211212000000167 is 761000000212112.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-211212000000167 is a prime.
It is a super-2 number, since 2×2112120000001672 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211212000060167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606000000083 + 105606000000084.
It is an arithmetic number, because the mean of its divisors is an integer number (105606000000084).
Almost surely, 2211212000000167 is an apocalyptic number.
211212000000167 is a deficient number, since it is larger than the sum of its proper divisors (1).
211212000000167 is an equidigital number, since it uses as much as digits as its factorization.
211212000000167 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 336, while the sum is 23.
Adding to 211212000000167 its reverse (761000000212112), we get a palindrome (972212000212279).
The spelling of 211212000000167 in words is "two hundred eleven trillion, two hundred twelve billion, one hundred sixty-seven", and thus it is an aban number.
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