Base | Representation |
---|---|
bin | 11110101111000100001… |
… | …110001101010000100111 |
3 | 21110220202100021211201201 |
4 | 132233010032031100213 |
5 | 234101110434012444 |
6 | 4254143415103331 |
7 | 305411220200632 |
oct | 36570416152047 |
9 | 7426670254651 |
10 | 2112121000999 |
11 | 744822273389 |
12 | 2a1415071b47 |
13 | 1242312c3049 |
14 | 74327628c19 |
15 | 39e1b3d9dd4 |
hex | 1ebc438d427 |
2112121000999 has 2 divisors, whose sum is σ = 2112121001000. Its totient is φ = 2112121000998.
The previous prime is 2112121000961. The next prime is 2112121001017. The reversal of 2112121000999 is 9990001212112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112121000999 - 233 = 2103531066407 is a prime.
It is a super-2 number, since 2×21121210009992 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112121000939) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056060500499 + 1056060500500.
It is an arithmetic number, because the mean of its divisors is an integer number (1056060500500).
Almost surely, 22112121000999 is an apocalyptic number.
2112121000999 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112121000999 is an equidigital number, since it uses as much as digits as its factorization.
2112121000999 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 37.
The spelling of 2112121000999 in words is "two trillion, one hundred twelve billion, one hundred twenty-one million, nine hundred ninety-nine", and thus it is an aban number.
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