Base | Representation |
---|---|
bin | 1100010010110100111… |
… | …0010000110101011111 |
3 | 202012011201211221121011 |
4 | 3010231032100311133 |
5 | 11430030300024244 |
6 | 241010212320051 |
7 | 21155014215565 |
oct | 3045516206537 |
9 | 665151757534 |
10 | 211212111199 |
11 | 81635804301 |
12 | 34b26613027 |
13 | 16bc01815bb |
14 | a319207a35 |
15 | 5762961434 |
hex | 312d390d5f |
211212111199 has 2 divisors, whose sum is σ = 211212111200. Its totient is φ = 211212111198.
The previous prime is 211212111193. The next prime is 211212111217. The reversal of 211212111199 is 991111212112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 211212111199 - 25 = 211212111167 is a prime.
It is a super-2 number, since 2×2112121111992 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 211212111199.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (211212111193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606055599 + 105606055600.
It is an arithmetic number, because the mean of its divisors is an integer number (105606055600).
Almost surely, 2211212111199 is an apocalyptic number.
211212111199 is a deficient number, since it is larger than the sum of its proper divisors (1).
211212111199 is an equidigital number, since it uses as much as digits as its factorization.
211212111199 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648, while the sum is 31.
The spelling of 211212111199 in words is "two hundred eleven billion, two hundred twelve million, one hundred eleven thousand, one hundred ninety-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •