Base | Representation |
---|---|
bin | 11110101111000100001… |
… | …110101010010111100111 |
3 | 21110220202100111220021201 |
4 | 132233010032222113213 |
5 | 234101111001321411 |
6 | 4254143421423331 |
7 | 305411221205353 |
oct | 36570416522747 |
9 | 7426670456251 |
10 | 2112121120231 |
11 | 744822344a21 |
12 | 2a141510ab47 |
13 | 1242313353b5 |
14 | 7432765a463 |
15 | 39e1b4103c1 |
hex | 1ebc43aa5e7 |
2112121120231 has 2 divisors, whose sum is σ = 2112121120232. Its totient is φ = 2112121120230.
The previous prime is 2112121120189. The next prime is 2112121120259. The reversal of 2112121120231 is 1320211212112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2112121120231 - 27 = 2112121120103 is a prime.
It is a super-2 number, since 2×21121211202312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112121120199 and 2112121120208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2112121120261) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056060560115 + 1056060560116.
It is an arithmetic number, because the mean of its divisors is an integer number (1056060560116).
Almost surely, 22112121120231 is an apocalyptic number.
2112121120231 is a deficient number, since it is larger than the sum of its proper divisors (1).
2112121120231 is an equidigital number, since it uses as much as digits as its factorization.
2112121120231 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 2112121120231 its reverse (1320211212112), we get a palindrome (3432332332343).
The spelling of 2112121120231 in words is "two trillion, one hundred twelve billion, one hundred twenty-one million, one hundred twenty thousand, two hundred thirty-one".
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