Base | Representation |
---|---|
bin | 1001100110101101010100… |
… | …10010101001100011101011 |
3 | 2202210011112112011101100111 |
4 | 10303112222102221203223 |
5 | 10232022220032204323 |
6 | 112530541145315151 |
7 | 4306646206040464 |
oct | 463265222514353 |
9 | 82704475141314 |
10 | 21121211209963 |
11 | 6803501110017 |
12 | 2451522a95ab7 |
13 | ba294c684607 |
14 | 5303b4817d6b |
15 | 269627aa4c0d |
hex | 1335aa4a98eb |
21121211209963 has 2 divisors, whose sum is σ = 21121211209964. Its totient is φ = 21121211209962.
The previous prime is 21121211209951. The next prime is 21121211210017. The reversal of 21121211209963 is 36990211212112.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21121211209963 - 225 = 21121177655531 is a prime.
It is a super-2 number, since 2×211212112099632 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21121211200963) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560605604981 + 10560605604982.
It is an arithmetic number, because the mean of its divisors is an integer number (10560605604982).
Almost surely, 221121211209963 is an apocalyptic number.
21121211209963 is a deficient number, since it is larger than the sum of its proper divisors (1).
21121211209963 is an equidigital number, since it uses as much as digits as its factorization.
21121211209963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23328, while the sum is 40.
The spelling of 21121211209963 in words is "twenty-one trillion, one hundred twenty-one billion, two hundred eleven million, two hundred nine thousand, nine hundred sixty-three".
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