Base | Representation |
---|---|
bin | 11110101111000100011… |
… | …011010000000000100100 |
3 | 21110220202120201112220021 |
4 | 132233010123100000210 |
5 | 234101112322421012 |
6 | 4254144020244524 |
7 | 305411261231146 |
oct | 36570433200044 |
9 | 7426676645807 |
10 | 2112124420132 |
11 | 744824199211 |
12 | 2a1416240744 |
13 | 124231c1c3bc |
14 | 74327c78c96 |
15 | 39e1b863007 |
hex | 1ebc46d0024 |
2112124420132 has 6 divisors (see below), whose sum is σ = 3696217735238. Its totient is φ = 1056062210064.
The previous prime is 2112124420069. The next prime is 2112124420157. The reversal of 2112124420132 is 2310244212112.
It can be written as a sum of positive squares in only one way, i.e., 1945673475876 + 166450944256 = 1394874^2 + 407984^2 .
It is a super-2 number, since 2×21121244201322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2112124420097 and 2112124420106.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 264015552513 + ... + 264015552520.
Almost surely, 22112124420132 is an apocalyptic number.
It is an amenable number.
2112124420132 is a deficient number, since it is larger than the sum of its proper divisors (1584093315106).
2112124420132 is a wasteful number, since it uses less digits than its factorization.
2112124420132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 528031105037 (or 528031105035 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 2112124420132 its reverse (2310244212112), we get a palindrome (4422368632244).
The spelling of 2112124420132 in words is "two trillion, one hundred twelve billion, one hundred twenty-four million, four hundred twenty thousand, one hundred thirty-two".
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