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2112124420132 = 22528031105033
BaseRepresentation
bin11110101111000100011…
…011010000000000100100
321110220202120201112220021
4132233010123100000210
5234101112322421012
64254144020244524
7305411261231146
oct36570433200044
97426676645807
102112124420132
11744824199211
122a1416240744
13124231c1c3bc
1474327c78c96
1539e1b863007
hex1ebc46d0024

2112124420132 has 6 divisors (see below), whose sum is σ = 3696217735238. Its totient is φ = 1056062210064.

The previous prime is 2112124420069. The next prime is 2112124420157. The reversal of 2112124420132 is 2310244212112.

It can be written as a sum of positive squares in only one way, i.e., 1945673475876 + 166450944256 = 1394874^2 + 407984^2 .

It is a super-2 number, since 2×21121244201322 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2112124420097 and 2112124420106.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 264015552513 + ... + 264015552520.

Almost surely, 22112124420132 is an apocalyptic number.

It is an amenable number.

2112124420132 is a deficient number, since it is larger than the sum of its proper divisors (1584093315106).

2112124420132 is a wasteful number, since it uses less digits than its factorization.

2112124420132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 528031105037 (or 528031105035 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2112124420132 its reverse (2310244212112), we get a palindrome (4422368632244).

The spelling of 2112124420132 in words is "two trillion, one hundred twelve billion, one hundred twenty-four million, four hundred twenty thousand, one hundred thirty-two".

Divisors: 1 2 4 528031105033 1056062210066 2112124420132