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211212910282697 is a prime number
BaseRepresentation
bin110000000001100011010110…
…011111010100011111001001
31000200211202102212112201211122
4300001203112133110133021
5210141003020013021242
62025113512123205025
762326425546165251
oct6001432637243711
91020752385481748
10211212910282697
116133198a5aa984
121b832588376775
1390b13a462071b
143a22a8bb30961
1519641ec2ebad2
hexc018d67d47c9

211212910282697 has 2 divisors, whose sum is σ = 211212910282698. Its totient is φ = 211212910282696.

The previous prime is 211212910282667. The next prime is 211212910282711. The reversal of 211212910282697 is 796282019212112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 180474800996281 + 30738109286416 = 13434091^2 + 5544196^2 .

It is a cyclic number.

It is not a de Polignac number, because 211212910282697 - 244 = 193620724238281 is a prime.

It is a super-2 number, since 2×2112129102826972 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (211212910282607) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105606455141348 + 105606455141349.

It is an arithmetic number, because the mean of its divisors is an integer number (105606455141349).

Almost surely, 2211212910282697 is an apocalyptic number.

It is an amenable number.

211212910282697 is a deficient number, since it is larger than the sum of its proper divisors (1).

211212910282697 is an equidigital number, since it uses as much as digits as its factorization.

211212910282697 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 870912, while the sum is 53.

The spelling of 211212910282697 in words is "two hundred eleven trillion, two hundred twelve billion, nine hundred ten million, two hundred eighty-two thousand, six hundred ninety-seven".