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211213001003340 = 2235717927110366903
BaseRepresentation
bin110000000001100011011011…
…111001011001000101001100
31000200211202200012020211011110
4300001203123321121011030
5210141003211224101330
62025113525123452020
762326431030252030
oct6001433371310514
91020752605224143
10211213001003340
1161331a26833716
121b8325b2827010
1390b13ba36568b
143a22a99bc81c0
15196420526bdb0
hexc018dbe5914c

211213001003340 has 192 divisors, whose sum is σ = 682165505064960. Its totient is φ = 47830397771520.

The previous prime is 211213001003273. The next prime is 211213001003353. The reversal of 211213001003340 is 43300100312112.

It is a super-5 number, since 5×2112130010033405 (a number of 73 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (21).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 15190329 + ... + 25557231.

It is an arithmetic number, because the mean of its divisors is an integer number (3552945338880).

Almost surely, 2211213001003340 is an apocalyptic number.

211213001003340 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 211213001003340, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (341082752532480).

211213001003340 is an abundant number, since it is smaller than the sum of its proper divisors (470952504061620).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

211213001003340 is a wasteful number, since it uses less digits than its factorization.

211213001003340 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10367372 (or 10367370 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 211213001003340 its reverse (43300100312112), we get a palindrome (254513101315452).

The spelling of 211213001003340 in words is "two hundred eleven trillion, two hundred thirteen billion, one million, three thousand, three hundred forty".