2112130113 has 4 divisors (see below), whose sum is σ = 2816173488. Its totient is φ = 1408086740.

The previous prime is 2112130109. The next prime is 2112130123. The reversal of 2112130113 is 3110312112.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2112130113 - 2² = 2112130109 is a prime.

It is a super-2 number, since 2×2112130113² = 8922187228482785538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2112130092 and 2112130101.

It is not an unprimeable number, because it can be changed into a prime (2112130123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352021683 + ... + 352021688.

It is an arithmetic number, because the mean of its divisors is an integer number (704043372).

Almost surely, 2^2112130113 is an apocalyptic number.

It is an amenable number.

2112130113 is a deficient number, since it is larger than the sum of its proper divisors (704043375).

2112130113 is an equidigital number, since it uses as much as digits as its factorization.

2112130113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 704043374.

The product of its (nonzero) digits is 36, while the sum is 15.

The square root of 2112130113 is about 45957.9167608803. The cubic root of 2112130113 is about 1283.0400788004.

Adding to 2112130113 its reverse (3110312112), we get a palindrome (5222442225).

The spelling of 2112130113 in words is "two billion, one hundred twelve million, one hundred thirty thousand, one hundred thirteen".