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21121310020200 = 2335213219531311579
BaseRepresentation
bin1001100110101101100000…
…01011100101001001101000
32202210011210102002110111220
410303112300023211021220
510232022420331121300
6112530555035222040
74306651515646125
oct463266013451150
982704712073456
1021121310020200
116803551969675
12245154bba7920
13ba2966c9c700
145303c39b974c
152696315c1da0
hex1335b02e5268

21121310020200 has 1152 divisors, whose sum is σ = 76668825024000. Its totient is φ = 4792595558400.

The previous prime is 21121310020177. The next prime is 21121310020229. The reversal of 21121310020200 is 202001312112.

It is a super-2 number, since 2×211213100202002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 21121310020200.

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 13376383011 + ... + 13376384589.

It is an arithmetic number, because the mean of its divisors is an integer number (66552799500).

Almost surely, 221121310020200 is an apocalyptic number.

21121310020200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21121310020200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (38334412512000).

21121310020200 is an abundant number, since it is smaller than the sum of its proper divisors (55547515003800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21121310020200 is a wasteful number, since it uses less digits than its factorization.

21121310020200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1827 (or 1805 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 21121310020200 its reverse (202001312112), we get a palindrome (21323311332312).

The spelling of 21121310020200 in words is "twenty-one trillion, one hundred twenty-one billion, three hundred ten million, twenty thousand, two hundred".