211213103113 has 4 divisors (see below), whose sum is σ = 211222076800. Its totient is φ = 211204129428.

The previous prime is 211213103063. The next prime is 211213103149. The reversal of 211213103113 is 311301312112.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-211213103113 is a prime.

It is a super-2 number, since 2×211213103113² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (211213103183) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4451445 + ... + 4498642.

It is an arithmetic number, because the mean of its divisors is an integer number (52805519200).

Almost surely, 2^211213103113 is an apocalyptic number.

It is an amenable number.

211213103113 is a deficient number, since it is larger than the sum of its proper divisors (8973687).

211213103113 is an equidigital number, since it uses as much as digits as its factorization.

211213103113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8973686.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 211213103113 its reverse (311301312112), we get a palindrome (522514415225).

The spelling of 211213103113 in words is "two hundred eleven billion, two hundred thirteen million, one hundred three thousand, one hundred thirteen".