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21121311130319 is a prime number
BaseRepresentation
bin1001100110101101100000…
…01111110100001011001111
32202210011210111011212022102
410303112300033310023033
510232022421122132234
6112530555115105315
74306651531251461
oct463266017641317
982704714155272
1021121311130319
116803552557724
12245155044223b
13ba296729aa9a
145303c3bc8131
15269631740c7e
hex1335b03f42cf

21121311130319 has 2 divisors, whose sum is σ = 21121311130320. Its totient is φ = 21121311130318.

The previous prime is 21121311130307. The next prime is 21121311130411. The reversal of 21121311130319 is 91303111312112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21121311130319 - 240 = 20021799502543 is a prime.

It is a super-2 number, since 2×211213111303192 (a number of 27 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 21121311130291 and 21121311130300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21121311135319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10560655565159 + 10560655565160.

It is an arithmetic number, because the mean of its divisors is an integer number (10560655565160).

Almost surely, 221121311130319 is an apocalyptic number.

21121311130319 is a deficient number, since it is larger than the sum of its proper divisors (1).

21121311130319 is an equidigital number, since it uses as much as digits as its factorization.

21121311130319 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 29.

The spelling of 21121311130319 in words is "twenty-one trillion, one hundred twenty-one billion, three hundred eleven million, one hundred thirty thousand, three hundred nineteen".