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2112131121211 is a prime number
BaseRepresentation
bin11110101111000100110…
…100110100000000111011
321110220210001100000001101
4132233010310310000323
5234101121031334321
64254144420032231
7305411402210626
oct36570464640073
97426701300041
102112131121211
11744827a558a1
122a1418532677
13124233427537
1474328b00dbd
1539e1c238791
hex1ebc4d3403b

2112131121211 has 2 divisors, whose sum is σ = 2112131121212. Its totient is φ = 2112131121210.

The previous prime is 2112131121209. The next prime is 2112131121259. The reversal of 2112131121211 is 1121211312112.

It is a m-pointer prime, because the next prime (2112131121259) can be obtained adding 2112131121211 to its product of digits (48).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2112131121211 - 21 = 2112131121209 is a prime.

It is a super-2 number, since 2×21121311212112 (a number of 25 digits) contains 22 as substring.

Together with 2112131121209, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2112131121011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056065560605 + 1056065560606.

It is an arithmetic number, because the mean of its divisors is an integer number (1056065560606).

Almost surely, 22112131121211 is an apocalyptic number.

2112131121211 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112131121211 is an equidigital number, since it uses as much as digits as its factorization.

2112131121211 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48, while the sum is 19.

Adding to 2112131121211 its reverse (1121211312112), we get a palindrome (3233342433323).

The spelling of 2112131121211 in words is "two trillion, one hundred twelve billion, one hundred thirty-one million, one hundred twenty-one thousand, two hundred eleven".