Search a number
-
+
2112131207 is a prime number
BaseRepresentation
bin111110111100100…
…1001000010000111
312110012100101022202
41331321021002013
513311201144312
6545330145115
7103224550634
oct17571110207
95405311282
102112131207
1199427448a
124ab42219b
132787777a4
1416072718b
15c56619c2
hex7de49087

2112131207 has 2 divisors, whose sum is σ = 2112131208. Its totient is φ = 2112131206.

The previous prime is 2112131201. The next prime is 2112131243. The reversal of 2112131207 is 7021312112.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2112131207 - 210 = 2112130183 is a prime.

It is a super-2 number, since 2×21121312072 = 8922196471166553698, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112131201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056065603 + 1056065604.

It is an arithmetic number, because the mean of its divisors is an integer number (1056065604).

Almost surely, 22112131207 is an apocalyptic number.

2112131207 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112131207 is an equidigital number, since it uses as much as digits as its factorization.

2112131207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 168, while the sum is 20.

The square root of 2112131207 is about 45957.9286630718. The cubic root of 2112131207 is about 1283.0403003217.

Adding to 2112131207 its reverse (7021312112), we get a palindrome (9133443319).

The spelling of 2112131207 in words is "two billion, one hundred twelve million, one hundred thirty-one thousand, two hundred seven".