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21121331300404 = 2218732819184637
BaseRepresentation
bin1001100110101101100010…
…11100110000100000110100
32202210011211220010121110121
410303112301130300200310
510232022441303103104
6112531001115301324
74306652164556416
oct463266134604064
982704756117417
1021121331300404
116803562983815
12245155714a844
13ba296b51074a
145303c67589b6
152696333c7254
hex1335b1730834

21121331300404 has 12 divisors (see below), whose sum is σ = 36982064081284. Its totient is φ = 10555027277184.

The previous prime is 21121331300339. The next prime is 21121331300417. The reversal of 21121331300404 is 40400313312112.

It can be written as a sum of positive squares in 2 ways, for example, as 1190285364004 + 19931045936400 = 1091002^2 + 4464420^2 .

It is a super-2 number, since 2×211213313004042 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1409584827 + ... + 1409599810.

Almost surely, 221121331300404 is an apocalyptic number.

It is an amenable number.

21121331300404 is a deficient number, since it is larger than the sum of its proper divisors (15860732780880).

21121331300404 is a wasteful number, since it uses less digits than its factorization.

21121331300404 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2819186514 (or 2819186512 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 21121331300404 its reverse (40400313312112), we get a palindrome (61521644612516).

The spelling of 21121331300404 in words is "twenty-one trillion, one hundred twenty-one billion, three hundred thirty-one million, three hundred thousand, four hundred four".

Divisors: 1 2 4 1873 3746 7492 2819184637 5638369274 11276738548 5280332825101 10560665650202 21121331300404