Base | Representation |
---|---|
bin | 1001100110101101100010… |
… | …11100110000100000110100 |
3 | 2202210011211220010121110121 |
4 | 10303112301130300200310 |
5 | 10232022441303103104 |
6 | 112531001115301324 |
7 | 4306652164556416 |
oct | 463266134604064 |
9 | 82704756117417 |
10 | 21121331300404 |
11 | 6803562983815 |
12 | 245155714a844 |
13 | ba296b51074a |
14 | 5303c67589b6 |
15 | 2696333c7254 |
hex | 1335b1730834 |
21121331300404 has 12 divisors (see below), whose sum is σ = 36982064081284. Its totient is φ = 10555027277184.
The previous prime is 21121331300339. The next prime is 21121331300417. The reversal of 21121331300404 is 40400313312112.
It can be written as a sum of positive squares in 2 ways, for example, as 1190285364004 + 19931045936400 = 1091002^2 + 4464420^2 .
It is a super-2 number, since 2×211213313004042 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1409584827 + ... + 1409599810.
Almost surely, 221121331300404 is an apocalyptic number.
It is an amenable number.
21121331300404 is a deficient number, since it is larger than the sum of its proper divisors (15860732780880).
21121331300404 is a wasteful number, since it uses less digits than its factorization.
21121331300404 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2819186514 (or 2819186512 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 21121331300404 its reverse (40400313312112), we get a palindrome (61521644612516).
The spelling of 21121331300404 in words is "twenty-one trillion, one hundred twenty-one billion, three hundred thirty-one million, three hundred thousand, four hundred four".
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