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2112133534541 is a prime number
BaseRepresentation
bin11110101111000100111…
…110000001001101001101
321110220210012212121111222
4132233010332001031031
5234101122141101131
64254144543453125
7305411431551602
oct36570476011515
97426705777458
102112133534541
11744829353a88
122a14192b71a5
13124233a90b44
147432916c6a9
1539e1c56387b
hex1ebc4f8134d

2112133534541 has 2 divisors, whose sum is σ = 2112133534542. Its totient is φ = 2112133534540.

The previous prime is 2112133534523. The next prime is 2112133534579. The reversal of 2112133534541 is 1454353312112.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1827133441225 + 285000093316 = 1351715^2 + 533854^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2112133534541 is a prime.

It is a super-2 number, since 2×21121335345412 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2112133834541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056066767270 + 1056066767271.

It is an arithmetic number, because the mean of its divisors is an integer number (1056066767271).

Almost surely, 22112133534541 is an apocalyptic number.

It is an amenable number.

2112133534541 is a deficient number, since it is larger than the sum of its proper divisors (1).

2112133534541 is an equidigital number, since it uses as much as digits as its factorization.

2112133534541 is an evil number, because the sum of its binary digits is even.

The product of its digits is 43200, while the sum is 35.

Adding to 2112133534541 its reverse (1454353312112), we get a palindrome (3566486846653).

The spelling of 2112133534541 in words is "two trillion, one hundred twelve billion, one hundred thirty-three million, five hundred thirty-four thousand, five hundred forty-one".